Last updated on September 27th, 2017 at 12:10 pm
Time and Work Problem with solution and Shortcut Tricks for Bank PO SSC Railway Exam Type-3
In time And work Type-3, 3.1 and Type-3.2. I am going to discuss some important Time And Work Problem with solution and Shortcut Tricks For Bank PO, SSC CGL, SSC CHSL, Railway Exam.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.
For Example:
(Q1)A, B, and C can do a piece of work in 10, 12, and 15 days respectively.They began the work together but B leaves after two days, how long would it take A and C to finish the Remaining work?
Solution:
Note: [L.C.M of 10,12,15=60 and 60/10=6, 60/12=5, 60/15=4]
Total work done by A, B, and C in 1 day=(6+5+4)unit=15 unit
[Concept: B 2 days बाद work छोड़ देता है, it means B के work छोडने से पहले A, B, and C तीनों 2 days तक एक साथ work किया होगा| so total work done by A, B, and C in 2 days=15×2=30 unit. Remaining work=60-30=30 unit. जब B work छोड़ दिया तो सिर्फ अब A and C बचा है तो total work done by A and C in 1 day=6+4=10 unit ]
Total work done by A, B, and C in 2 day=15×2=30 unit
Remaining work=60-30=30 unit
When B left the job then
Total work done by A and C in 1 day=6+4=10 unit
Time taken by A and C=30/10
=3 days Ans.
(Q2)A, B, and C can do a piece of work in 20, 25, and 30 days respectively.They began the work together but C leaves after 3 days. In how many days the whole work was completed?
Solution:
Note: [L.C.M of 20,25,30=300 and 300/20=15, 300/25=12, 300/30=10]
Work done by A, B, and C in 1 day=(15+12+10)unit=37 unit
[Concept: C 3 days बाद work छोड़ देता है, it means C के work छोडने से पहले A, B, and C तीनों 3 days तक एक साथ work किया होगा| so total work done by A, B, and C in 3 days=37×3=111 unit. Remaining work=300-111=189 unit. जब C work छोड़ दिया तो सिर्फ अब A and B बचा है तो total work done by A and B in 1 day=15+12=27 unit.]
Total work done by A, B, and C in 3 day=37×3=111 unit
Remaining work=300-111=189 unit
When C left the work then
Work done by A+B in 1 day=15+12=27 unit
Time taken by (A+B)=189/27
=7 days
The whole work was completed in=3+7
=10 days Ans.
(Q3)A, B, and C together can do a piece of work in 40 days. After working with A, B and C for 16 days, A leaves and then B and C complete the remaining work in 40 days more. A alone could do the work in.
Solution:
Let work done by (A+B+C) in per day=1 unit
Total work done by (A+B+C) in 40 day=40 unit
Total work done by (A+B+C) in 16 day=16 unit
Now,
Remaining work=40-16=24 unit
[Concept: 24 unit work अब सिर्फ B and C करेगा जिसे करने में B and C को 40 days लग रहा है क्योंकि A ने work छोड़ दिया है |]
work done by B and C in 40 days =24 unit
work done by B and C in 1 day =24/40
=0.6 unit
Efficiency(eff.) of A=Eff. of(A+B+C)-Eff. of (B+C)
= 1-0.6=0.4 unit per day
Time taken by A=40/0.4=100 days Ans.
(Q4)A, B, and C can do a job in 6 days, 12 days and 15 days respectively. After 1/8 of the work is completed, C leaves the job. Rest of the work is done by A and B together. Time taken to finish the work is.
Solution:
[Concept: 60×(1/8)=7.5 unit. जब 7.50 unit work complete हो गया तब C ने job छोड़ दिया now remaining work=60-7.50=52.50 unit. 52.50 unit work सिर्फ A and B मिलकर कर रहा है|]
Now,
60×(1/8)=7.5 unit
Remaining work=60-7.50=52.50 unit
Work done by A +B in 1 days=10+5=15 unit
Time taken by (A+B)=52.50/15
=7/2=3 ½ days Ans.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.1.
(Q1)A, B, and C can do a piece of work in 15, 20, and 12 days respectively. They began the work together but A left 5 days before completion of the work. In how many days was the work done?
Solution:
Note: [L.C.M of 15,20,12=60 and 60/15=4, 60/20=3, 60/12=5]
[Concept: A work complete होने के 5 days पहले चला जाता है तो work complete होने में जो 5 days बचा था तो उसमे सिर्फ B and C ने ही work किया so, work done by B and C in 1 days=3+5=8 unit ∴work done by B and C in 5 days=8×5=40 unit. remaining work 60-40=20 unit. 20 unit work A, B, and C ने मिलकर किया होगा ]
Work done by B and C in 1 day=(3+5)unit=8 unit
Total work done by B and C in 5 day=8×5=40 unit
Remaining Work=60-40=20 unit
Work done by A, B, and C in 1 day=(4+3+5)unit=12 unit
Now,
20 unit work is done by A, B and C so,
Time taken by (A+B+C)=20/12
=5/3 days
Total time=5+(5/3)
=20/3 days Ans.
(Q2)A, B, and C can do a piece of work in 24, 30, and 40 days respectively. They began the work together but C left 4 days before completion of the work. In how many days was the work done?
Solution:
[Concept: C work complete होने के 4 days पहले चला जाता है तो work complete होने में जो 4 days बचा था तो उसमे सिर्फ A and B ने ही work किया so, work done by A and B in 1 days=5+4=9 unit ∴work done by A and B in 4 days=9×4=36 unit. remaining work 120-36=84 unit. 84 unit work A, B, and C ने मिलकर किया होगा ]
Work done by A and B in 1 day=(5+4)unit=9 unit
Total work done by A and B in 4 day=9×4=36 unit
Remaining Work=120-36=84 unit
Work done by A, B, and C in 1 day=(5+4+3)unit=12 unit
Now,
84 unit work is done by A, B and C so,
Time taken by (A+B+C)=84/12
=7 days
Total time=4+7=11 days Ans.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.2.
(Q1)A, B, and C can complete a work separately in 24, 36, and 48 days respectively. They started work together but C left after 4 days of start and A left 3 days before the completion of the work. In how many days will the work be completed.
Solution:
[Concept: C work start होने के 4 days बाद work छोड़ कर चला जाता है| it means C के जाने से पहले A, B, and C ने 4 days तक एकसाथ work किया है so, work done (A+B+C) in 1 day=(6+4+3)=13 unit ∴work done (A+B+C) in 4 day=13×4=52 unit Remaining work=144-52=92 unit.]
Work done (A+B+C) in 1 day=(6+4+3)=13 unit
Work done (A+B+C) in 4 day=13×4=52 unit
Remaining work=144-52=92 unit.
[concept: C तो पहले ही जा चुका है अब सिर्फ A and B बचा है. now question में कह रहा है A work complete होने से 3 days पहले चला जाता है तो last 3 days सिर्फ B ने ही work किया होगा so work done by B in 3 days=3×4=12 unit. remaining work=92-12=80 unit. 80 unit work A and B ने मिलकर किया है |]
Now,
Work done by B in 3 days=3×4=12 unit
Remaining work=92-12=80 unit
Work done by (A+B) in 1 day=(6+4)=10 unit
Time taken by (A+B)=80/10
=8 days
Total time=(4+3+8)=15 days Ans.
(Q2)A, B, and C can do a work separately in 16, 32, and 48 days respectively. They started the work together but B left off 8 days and C 6 days before the completion of the work. In what time is the work finished?
Solution:
[Concept– B work complete होने के 8 days before चला जाता है तो work करने के लिए अब सिर्फ A and C बचा| so work done by (A+C) in 1 day=6+2=8 unit ∴ work done by (A+C) in 2 day=8×2=16 unit. remaining work=96-16=80 unit. यहाँ पर A and C का 2 days का ही work निकाला गया है क्योंकि question में कह रहा है कि work complete होने से 6 days before फिर C चला जाता है that means B के जाने के 2 days बाद ही C चला जाता है| अब last का 6 days work करने के लिए सिर्फ A ही बच जाता है| so work done by A in 6 day=6×6=36 unit. remaining work=80-36=44 unit.ये 44 unit work A, B and C ने मिलकर किया है |]
Work done by (A+C) in 1 day=6+2=8 unit
∴ Work done by (A+C) in 2 day=8×2=16 unit.
Remaining work=96-16=80 unit.
Work done by A in 6 day=6×6=36 unit
Remaining work=80-36=44 unit.
Time taken by (A+B+C)=44/11
=4 days
Total days=2+6+4=12 days Ans.
Method-2
Let the whole work be completed in x days
According to the question,
(Q3)A, B and C can complete a work in 10, 12 and 15 days respectively. A left the work 5 days before the work was completed and B left 2 days after A had left. Number of days required to complete the whole work is:
Solution:
[Concept- A work complete होने के 5 days before चला जाता है तो work करने के लिए अब सिर्फ B and C बचा| so work done by (B+C) in 1 day=5+4=9 unit ∴ work done by (B+C) in 2 day=9×2=18 unit. remaining work=60-18=42 unit. यहाँ पर B and C का 2 days का ही work निकाला गया है क्योंकि question में कह रहा है कि B left 2 days after A had left means A के जाने के 2 days बाद ही B चला जाता है that means work complete होने में 3 days बचा ही था कि B work छोड़ चला जाता है | अब last का 3 days work करने के लिए सिर्फ C ही बच जाता है| so work done by C in 3 day=4×3=12 unit. remaining work=42-12=30 unit.ये 30 unit work A, B and C ने मिलकर किया है |]
Work done by (B+C) in 1 day=5+4=9 unit
∴ Work done by (B+C) in 2 day=9×2=18 unit.
Remaining work=60-18=42 unit
now,
Work done by C in 3 day=4×3=12 unit
Remaining work=42-12=30 unit
Time taken by (A+B+C)=30/15
=2 days
Total days=2+3+2=7 days Ans.
Method-2
Let the whole work be completed in x days
According to the question,
Time and work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-2.In this type, I have already shared a time and work Problem with solution, Shortcut Tricks, Basic concept and frequently asked question if you have not read that yet, you should read it the right way here is the link.
Time and work Problem Shortcut Tricks Type-2
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