Last updated on July 2nd, 2018 at 11:54 am
Percentage Shortcut Tricks Bank PO SSC Railway Exams type-9.
In type-9, I have discussed a question based on Depreciation and population increase. This type of percentage problem frequently asked in Bank, SSC, Railways Exam.
(Q1)The population of a town increases by 5% every year. If the present population is 9261, The population 3 Years ago was.
Solution: F.Q=I.Q×M.F
Where I.Q=Initial Quantity
F.Q=Final Quantity
M.F=Multiplying Factor
Now
F.Q=I.Q×M.F
9261=I.Q×(105/100)×(105/100)×(105/100)
I.Q=(9261×100×100×100)/(105×105×105)
=8000 Ans
CONCEPT:[इस Type के Question को Solve करते Time आपलोगो को सिर्फ इन बातों पर ध्यान रखना है Question में After n Years का value निकालने के लिए कह रहा है या n Years Ago का | (1)यदि Question में After n Years का value निकालने के लिए कह रहा हो तो Present value जो Question में दिया होगा वह Initial Quantity होगा| (2) यदि Question में n Years Ago का value निकालने के लिए कह रहा हो तो Present value जो Question में दिया होगा वह Final Quantity होगा|]
(Q2)The present population of a city is 180000. If it increases at the rate of 10%per annum, its population after 2 years will be.
Solution: F.Q=I.Q×M.F
F.Q=180000×(110/100)×(110/100)
=217800 Ans.
(Q3)The present price of a scooter is 7290. If its value decreases every year by 10%, then its value after 3 years back was.
Solution: F.Q=I.Q×M.F
7290=I.Q×(90/100)×(90/100)×(90/100)
∴ I.Q=(7290×100×100×100)/(90×90×90)
=10000 Ans.
(Q4)In a factory, the production of cycles rose to 48,400 from 40,000 in 2 years. The rate of growth per annum is.
Solution: Let rate of growth=x%
F.Q=I.Q×M.F
48,400=40000×((100+x)/100)×(100+x)/100
48,400/4=(100+x)²
12100=(100+x)²
(110)²=(100+x)²
100+x=110
∴ x=10% Ans
(Q5)The population of a village was 9800. In a year with the increase in the population of males by 8% and that of females by 5%, the population of the village become 10458.What was the number of males in the village before increase?
Solution:Let the number of males=x
∴ number of females=9800-x
x×(108/100)+(9800-x)×(105/100)=10458
=>108x+9800×105-105x=1045800
=>3x=1045800-1029000
=16800
∴ x=16800/3
=5600 Ans.
Percentage Shortcut Tricks Bank PO SSC Railway Exams type-9.1.
(Q1)A large watermelon weighs 20kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that only 95% of its weight is water.Its reduced weight will be:
Solution:
Weight of fresh watermelon=20Kg
the weight of fresh pulp=20×(4/100)
=0.8Kg
Now,
Concept:[watermelon में से water सूखेगा न कि pulp. pulp तो always same ही रहेगा चाहे Fresh हो या Dry ]
so,
5%=0.8Kg
1%=0.8/5 Kg
∴ 100%=(0.8/5)×100 Kg
=16 Kg Ans.
(Q2)Fresh grapes contain 80% water while Dry grapes contain 10% water. If the weight of dry grapes is 500Kg then what is its total weight when it is fresh.
Solution:
Weight of Dry grapes=500Kg
the weight of Dry pulp=500×(90/100)
=450Kg
Now,
Concept:[Grapes में से water सूखेगा न कि pulp. pulp तो always same ही रहेगा चाहे Fresh हो या Dry ]
so,
20%=450Kg
1%=450/20 Kg
∴ 100%=(450/20)×100 Kg
=2250 Kg Ans.
Percentage Shortcut Tricks Bank PO SSC Railway Exams type-8.In this type, I have already shared a percentage problem based on Income, Expenditure, and salary if you have not read that yet, you should read it the right way here is the link.
If you have any queries regarding this topic feel free to ask me in the comments below.
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