Important Percentage Problem Concepts And Shortcut Tricks Type-7

0
6602
Share this Post On:

Percentage calculation shortcut tricks for Bank SSC Railways type-7. In type-7 I have discussed a question based on Voters in an Election. This type of problem frequently asked in Bank,SSC,Railways Exam.

(Q1)In an election, there were only two candidates. one of the candidates secured 40% of votes and is defeated by the other candidate by 298 votes. The total number of votes polled is.

Solution:Let total votes=100x

percentage calculation shortcut tricks

Now,

60x-40x=298

=>20x=298

∴ x=298/20

=14.6

Total votes=100x

=100×14.6

=1460 votes Ans.

Rough:

100x×(40/100)

=40x

100x×(60/100)

=60x

(Q2)In an election between two candidates, the candidate getting 60% of the votes polled,is elected by a majority of 14000 votes . The number of votes polled by the winning candidate is.

Solution:

percentage calculation shortcut tricks

60x-40x=14000

20x=14000

∴ x=14000/20

=700

Number of votes polled by the winning candidate=60x

=60×700

=42000 votes Ans.

(Q3)8% of the votes in an election did not cast their votes. In this election,there only two candidates.The winner by obtaining 48% of the total votes defeated his contestant by 1100 votes. The total number of voters in the election was.

Solution:

percentage calculation shortcut tricks

Now,

48x-44x=1100

=>4x=1100

∴ x=1100/4

Total number of voter=100x

=100×(1100/4)

=27500 voters Ans

Concept:[8% of the voters in an election did not cast their votes, it means only 92% voter cast their votes now winner candidates secure 48% votes ∴ Loser candidate=92%-48%=44%]

(Q4)In an election between two candidates,One got 55% of the total valid votes,20% of the votes were invalid.If the total number of votes was 7500,the number of valid votes that the other candidate got,was.

Solution:Total number of votes =7500

20% invalid votes

i.e 7500×(20/100)

=1500 invalid votes.

now valid votes=7500-1500=6000 votes

one candidate got 55% of the total valid votes

i.e 6000×(55/100)

=3300 votes

2nd candidate got=6000-3300

=2700 votes Ans.

(Q5)10% of the voters did not cast their vote in an election between two candidates.10% of the votes polled were found invalid. The successful candidate got 54% of the valid votes and won by a majority of 1620 votes. The numbers of voters enrolled on the voter list.

Solution:Let the numbers of voters enrolled on the voter list=100x

percentage calculation shortcut tricks

Now,

81x×(54/100)-81x×(46/100)=1620

81x[(54/100)-(46/100)]=1620

∴ x=(1620×100)/(81×8)

=250

The numbers of voters enrolled on the voter list=100x

=100×250

=25000 Ans.

Rough:

10% did not cast their votes

i.e 100x×(10/100)

=10x voter did not cast vote

∴ casting vote=100x-10x=90x

10% invalid votes of 90x

i.e 90x(10/100)

=9x

∴ valid votes=90x-9x=81x

In percentage type-6 I have already shared a percentage problem based on Examination and Marks obtained if you have not read that yet,you should  read it the right way here is the link.

Percentage Problem Type-6

If you have any queries regarding this topic fell free to ask me in the comments below.

Did you like this article? Share it with your friends on facebook,Twitter,Whatsapp and Google plus!

LEAVE A REPLY

Please enter your comment!
Please enter your name here