Last updated on July 2nd, 2018 at 12:01 pm
Percentage problem shortcut tricks for Bank PO SSC Railway Exam
Today I am going to talk about percentage type-4. In this type, I have discussed a common type percentage problem that is frequently asked in Bank PO SSC Railway exam.
For Example: The price of sugar having gone down by 10%,sharad can buy 6.2Kg more for Rs.279.The difference between the original and the reduced price(per Kg) is:
And another example is:The price of sugar is decreased by 25%.Therefore a family increases its consumption so that the decrement in the expenditure of sugar is only 15%.if the consumption of sugar is 30Kg before the decrement,what is the consumption now.
Common Type Of Percentage Problem That Is Frequently Asked In BANK PO SSC RAILWAY EXAM
(Q1)Due to increase in the price of sugar by 30% a man can buy 6kg less for Rs.520.then find out the original price per kg in Rs.?
Solution:Let original price=Rs 100
Now
Step-1
[Original price=Rs 100,New price=Rs130,Original quantity=130Kg,New Quantity=100Kg And Decreased quantity=30Kg]
Concept:According to Question A man can buy 6Kg less.But यहाँ पर 30Kg कम निकल रहा है,तो अब 30Kg को 6Kg बनाना होगा इसके लिए Quantity वाले part में 5 से Divide करना होगा|
[Concept in English:According to Question A man can buy 6Kg less.but here we got 30Kg less, so we will have to make 6kg, therefore, quantity divide by 5]
Step-2
price of 26 kg=Rs520
∴ Price of 1Kg=520/26
=Rs20 Ans.
Concept:[जब Expenditure same रहेगा तब इस process से solve करना है|इस Question में Expenditure same क्योंकि पहले Rs520 में जितना खरीदता था अब price increase होने से Rs520 में 6kg कम खरीद पा रहा है ]
BY TRICK:
Original price=(30×520)/(100+30)×6
=(30×520)/(130×6)
= Rs20 Ans.
(Q2)Due to a decrease in the price of sugar by 20% a man can buy 4Kg more for Rs80 then find the original price per Kg in Kg?
Solution:Let original price=Rs100
Step-1
[Original price=Rs 100,New price=Rs80,Original quantity=80Kg,New Quantity=100Kg And Increased quantity=20Kg]
Concept:According to Question A man can buy 4Kg more.But यहाँ पर 20Kg अधिक निकल रहा है,तो अब 20Kg को 4Kg बनाना होगा इसके लिए Quantity वाले part में 5 से Divide करना होगा|
[Concept in English:According to Question A man can buy 4Kg more.but here we got 20Kg more, so we will have to make 4kg, therefore, quantity divide by 5]
Step-2
the price of 16kg=Rs80
∴ price of 1Kg=80/16
=Rs 5 Ans.
BY TRICK:
Original price=(20×80)/(100-20)×4
=(20×80)/(80×4)
= Rs.5 Ans.
(Q3)A reduction of 21% in the price of wheat enables a person to buy 10.5kg more for Rs.100.what is the reduced price per Kg?
Solution:Let original price=Rs.100
Step-1
Step-2
Price of 50Kg=Rs.100
∴price of 1Kg=100/50
=Rs.2 Ans
BY TRICK:
Reduced price=(21×100)/(100×10.5)
=Rs.2 Ans
(Q4)The price of sugar having gone down by 10%,sharad can buy 6.2Kg more for Rs.279.The difference between the original and the reduced price(per Kg) is:
Solution:Let original price=Rs.100
Step-1:
Step-2:
(1)Original price:
Price of 90×0.62Kg=Rs.279
∴ price of 1Kg=279/(90×0.62)
=Rs.5/Kg Ans.
(2)Reduced price:
Price of 100×0.62Kg=Rs.279
∴ price of 1Kg=279/(100×0.62)
=Rs.4.5/Kg Ans
Difference=5-4.5
=Rs.0.5 Ans.
BY TRICK:
Original price=10×279/(100-10)×6.2
=10×279/(90×6.2)
=Rs.5/Kg
Reduced price=10×279/(100×6.2)
=Rs.4.5/Kg
IMPORTANT PERCENTAGE PROBLEM CONCEPTS AND SHORTCUT TRICKS FOR BANK PO SSC RAILWAY EXAM TYPE-4.1
(Q1)The price of sugar is increased by 30%.Therefore a family reduces its consumption so that the increment in the expenditure of sugar is only 10%.if the consumption of sugar is 26Kg before the increment,what is the consumption now.
Solution:We know that
∴ X=286/13
=22Kg Ans
ROUGH:
Rs10 increased by 30% then,
=10×(100+30)/100
=Rs13
Rs260 increased by 10% then,
260×(100+10)/100
=(260×110)/100
=Rs286
BY TRICK:
Consumption=26×(100+10)/(100+30)
=26×110/130
=22Kg Ans.
(Q2)The price of sugar is decreased by 25%.Therefore a family increases its consumption so that the decrement in the expenditure of sugar is only 15%.if the consumption of sugar is 30Kg before the decrement,what is the consumption now.
Solution:
∴ X=255/7.50
=34Kg Ans.
ROUGH:
Rs300 decreased by 15% then
300×(100-15)/100
=(300×85)/100
=255
Rs10 decreased by 25% then,
10×(100-25)/100
=(10×75)/100
=7.50
BY TRICK:
consumption:30×(100-15)/100-25
=(30×85)/75
=34Kg Ans.
I have already shared an important percentage problem concepts and shortcut tricks for Bank PO SSC Railway EXAM. If you have not done that yet, you should do it the right way here is the link.
If you have any queries regarding this topic feel free to ask me in the comments below.
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Typical questions but nice approach
nice trick to solve complicated problems. Thanks for your effort. But can you please add english explanation for step 2 in first problem. There are many students here in south also your follows your blog.
Thanks sir.