Important Profit and Loss Problem Shortcut Tricks Bank PO SSC Railway Exam Type-5

Last updated on July 13th, 2017 at 12:10 am

Profit and Loss problem Shortcut Tricks for Bank PO SSC Railway Exam Type-5

In Profit And Loss Type-5, 5.1 and Type -5.2, I am going to discuss some important Profit And Loss problem with a solution and Shortcut Tricks For Bank PO, SSC CGL, SSC CHSL, Railway Exam.

The common and frequently asked a question of Profit and Loss problem with a solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-5.

For Example:

(Q1)By selling a chair for Rs 350 instead of Rs 400, loss percent increases by 5%. The cost price of the chair is.

Solution: By Trick:

C.P=((400-350)/5)×100

=(50/5)×100

=Rs 1000 Ans.

BY CONCEPT:

S.P1=Rs 350

S.P2=Rs 400

Let C.P=x

Loss1(L1)=x-350

Loss2(L2)=x-400

%L1=((x-350)×100)/x

Note: % loss=(loss×100)/C.P

%L2=((x-400)×100)/x

Now,

L%=L1% – L2%

5=((x-350)×100)/x – ((x-400)×100)/x

5=100/x(x-350 – x-400)

5=(100/x)×50

5x=100×50

x= Rs 1000 Ans.

(Q2)5% more is gained by selling a cow for Rs 1010 than by selling it for Rs 1000. Find the cost price of the cow.

Solution: By Trick:

C.P=((1010-1000)/5)×100

=(10/5)×100

=Rs 200 Ans.

BY CONCEPT:

S.P1=Rs 1010

S.P2=Rs 1000

Let C.P=x

Profit1(P1)=1010-x

Profit2(P2)=1000-x

%P1=((1010-x)×100)/x

Note: % Profit=(Profit×100)/C.P

%P2=((1000-x)×100)/x

Now,

P%=P1% – P2%

5=((1010-x)×100)/x – ((1000-x)×100)/x

5=100/x(1010-x – 1000-x)

5=(100/x)×10

5x=100×10

x= Rs 200 Ans.

(Q3) A loss of 19% gets converted into a profit of 17% when the selling price is increased by Rs 162. The cost price of the article is.

Solution: By Concept:

[Concept: according to question 19% के loss पर जो selling price है  उसमे Rs 162 increased करने पर loss convert हो गया 17% profit में so 81x+162=117x]

Now,

81x+162=117x

36x=162

∴ x=4.5

C.P=100x=100×4.5

=Rs 450 Ans.

BY TRICK:

C.P=(162×100/(17+19)

=(162×100)/36

=Rs 450 Ans.

The common and frequently asked a question of Profit and Loss problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-5.1

TRICK:

The profit obtained by selling an article for Rs X is same as the loss incurred if it is sold for Rs Y then

For Example:

(Q1)The profit obtained by selling an article for Rs 340 is same as the loss incurred if it is sold for Rs 248. Find the C.P.

Solution: By Concept

Let C.P=x

Profit=340-x    [Profit=S.P-C.P]

Loss=x-248      [Loss=C.P-S.P]

Now, According to Question

340-x=x-248

-2x=-588

∴ x= Rs 294

So, C.P=Rs 294 Ans

By Trick:

C.P=(340+248)/2

=Rs 294 Ans

(Q2)The profit obtained by selling a table for Rs 625 is same as the loss incurred if it is sold for Rs 545. The price at which it is to be sold to realize a profit of Rs 65 on the cost price is.

Solution: By Concept

Let C.P=x

Profit=625-x    [Profit=S.P-C.P]

Loss=x-545      [Loss=C.P-S.P]

Now, According to Question

625-x=x-545

2x=1170

x= Rs 585

∴ Required S.P=Rs(585+65)

= Rs 650 Ans

By Trick:

C.P=(625+545)/2

=Rs 585 Ans

∴ Required S.P=Rs(585+65)

= Rs 650 Ans

(Q3)The profit earned by selling an article for Rs 832 is equal to the loss incurred when the same article is sold for Rs 448. What should be the sale price for making 50% profit?

Solution: By Concept

Let C.P=x

Profit=832-x    [Profit=S.P-C.P]

Loss=x-448      [Loss=C.P-S.P]

Now, According to Question

832-x=x-448

2x=1280

x= Rs 640

Now,

640×(100+50)/100=S.P

640×(150/100)=S.P

S.P=Rs 960 Ans.

By Trick:

C.P=(832+448)/2

=Rs 640

Now,

640×(100+50)/100=S.P

640×(150/100)=S.P

S.P=Rs 960 Ans.

The common and frequently asked a question of Profit and Loss problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-5.2.

TRICK:

The profit earned by selling an article for Rs X is n times the loss incurred when the same article is sold for Rs Y. Then

For Example:

(Q1)The profit earned by selling an article for Rs 900 is double the loss incurred when the same article is sold for Rs 450. At what price should the article be sold to make 25% profit?

Solution: By Concept

Let C.P=x

Profit=900-x    [Profit=S.P-C.P]

Loss=x-450      [Loss=C.P-S.P]

Now, According to Question

900-x=2(x-450)

3x=1800

x= Rs 600

Now,

600×(100+25)/100=S.P

600×(125/100)=S.P

S.P=Rs 750 Ans.

By Trick:

C.P=(900+2×450)/(2+1)

=1800/3

=Rs 600

Now,

600×(100+25)/100=S.P

600×(125/100)=S.P

S.P=Rs 750 Ans.

(Q2)Profit earned by selling an article for Rs 1060 is 20% more than the loss incurred by selling the article for Rs 950. At what price should the article be sold to earn 20% profit?

Solution: By Concept

Let C.P=x

Profit=1060-x    [Profit=S.P-C.P]

Loss=x-950      [Loss=C.P-S.P]

Now, According to Question

1060-x=(120/100)×(x-950)

5(1060-x)=6(x-950)

5300-5x=6x-5700

-11x=-11000

x= Rs 1000

Now,

1000×(100+20)/100=S.P

S.P=Rs 1200 Ans.

BY TRICK:

C.P=(1060+(120/100)×950)/(120/100)+1

=(1060+95×12)/(22/10)

=Rs 1000

Now,

1000×(100+20)/100=S.P

S.P=Rs 1200 Ans.

(Q3)A shopkeeper sells an article for Rs 140 and earns double the profit that he would have earned had he sold it for Rs 120. What is its cost price?

Solution: By trick

C.P=(2×120-140)/2-1

=Rs 100 Ans.

By Concept:

Let C.P=x

Profit=140-x    [Profit=S.P-C.P]

Profit=120-x

Now, According to Question

140-x=2×(120-x)

x=Rs 100 Ans.

Profit and Loss problem with a solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.In this type, I have already shared a Profit and Loss problem with a solution, Shortcut Tricks, Basic concept and frequently asked question if you have not read that yet, you should read it the right way here is the link.

Profit and Loss Concepts Shortcut Tricks Type-4

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