Last updated on December 29th, 2016 at 01:24 pm
Profit and Loss question with solution and Shortcut Tricks for Bank PO SSC Railway Exam Type-4
In Profit And Loss Type-4 and Type-4.1. I am going to discuss some important Profit And Loss question with solution and Shortcut Tricks For Bank PO, SSC CGL, SSC CHSL, Railway Exam.
The common and frequently asked problem of Profit and Loss question with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.
For Example:
TRICK-1
If two article are sold at equal prices, the first one is sold at P1% Profit and whereas the second one at a Profit of P2% And the sum of the cost price of two article is x then
For Example:
(Q1) A trader bought two watches for Rs 2300. He sold one at a profit of 10% and the other at a profit of 20%. If the selling price of each watch is the same, then their cost price are respectively.
Solution: By Trick:
C.P of watch at a profit of 10%=((100+20)/(200+10+20))×2300
=(120/230)×2300
=Rs 1200 Ans.
C.P of watch at a profit of 20%=Rs(2300-1200)
=Rs 1100 Ans.
BY CONCEPT:
Let C.P of 1st watch=x
C.P of 2nd watch=2300-x
S.P of 1st watch:
x×(100+10)/100=S.P1
11x/10=S.P1
S.P of 2nd watch:
(2300-x)×(100+20)/100=S.P2
(2300-x)×120/100=S.P2
(2300-x)×12/10=S.P2
Now According to question: selling price of each watch is the same
SO,
S.P1=S.P2
11x/10=(2300-x)×12/10
11x=2300×12-12x
23x=2300×12
x=Rs 1200 Ans
C.P of 2nd watch=2300-x
=Rs(2300-1200)
=Rs 1100 Ans.
TRICK-2
If two article are sold at equal prices, the first one is sold at a Loss of L1% and whereas the second one at a Loss of L2%, And the sum of the cost price of two article is x then
For Example:
(Q1) A Man purchases two T.V sets for Rs 21,500. He sold one at a Loss of 12% and the other at a loss of 16%. If the selling price of each T.V is the same, then their cost price are respectively.
Solution: By Trick:
C.P of T.V at a Loss of 12%=((100-16)/(200-12-16))×21500
=(84/172)×21500
=Rs 10500 Ans.
C.P of T.V at a Loss of 16%=Rs(21500-10500)
=Rs 11000 Ans.
BY CONCEPT:
Let C.P of 1st T.V =x
C.P of 2nd T.V=21500-x
S.P of 1st T.V:
x×(100-12)/100=S.P1
88x/100=S.P1
S.P of 2nd T.V:
(21500-x)×(100-16)/100=S.P2
(21500-x)×84/100=S.P2
(21500-x)×84/100=S.P2
Now According to question: selling price of each T.V is the same
SO,
S.P1=S.P2
88x/100=(21500-x)×84/100
88x=21500×84-84x
172x=21500×84
x=Rs 1o500 Ans
C.P of 2nd T.V=21500-x
=Rs(21500-10500)
=Rs 11000 Ans.
TRICK-3
If two article are sold at equal prices, the first one is sold at a Profit of P% and whereas the second one at a Loss of L%, And the sum of the cost price of two article is x then
For Example:
(Q1) A Man purchases two horses for Rs 16,800. He sold one at a Profit of 25% and the other at a loss of 15%. If the selling price of each horse is the same, then their cost price are respectively.
Solution: By Trick:
C.P of horse at a profit of 25%=((100-15)/(200+25-15))×16800
=(85/210)×16800
=(85/210)×16800
=Rs 6800 Ans.
C.P of horse at a Loss of 15%=Rs(16800-6800)
= Rs 10000 Ans.
BY CONCEPT:
Let C.P of 1st horse=x
C.P of 2nd horse=16800-x
S.P of 1st horse:
x×(100+25)/100=S.P1
125x/100=S.P1
S.P of 2nd horse:
(16800-x)×(100-15)/100=S.P2
(16800-x)×85/100=S.P2
(16800-x)×85/100=S.P2
Now According to question: selling price of each horse is the same
SO,
S.P1=S.P2
125x/100=(16800-x)×85/100
125x=16800×85-85x
210x=16800×85
x=Rs 6800 Ans
C.P of 2nd horse=16800-x
=Rs(16800-6800)
=Rs 10000 Ans.
TRICK-4
If two article are sold at equal prices, the first one is sold at a Loss of L% and whereas the second one at a Profit of P%, And the sum of the cost price of two article is x then
For Example:
(Q1) A trader bought two horses for Rs 19,500. He sold one at a Loss of 20% and the other at a Profit of 15%. If the selling price of each horse is the same, then their cost price are respectively.
Solution: By Trick:
C.P of horse at a Loss of 20%=((100+15)/(200-20+15))×19500
=(115/195)×19500
=Rs 11500 Ans.
C.P of horse at a Profit of 15%=Rs(19500-11500)
=Rs 8000 Ans.
The common and frequently asked problem of Profit and Loss question with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.1.
(Q1)The total cost price of two watches is Rs 840. One is sold at a profit of 16% and the other at a loss of 12%. There is no loss or gain in the whole transition. Then their cost price is respectively.
Solution: BY CONCEPT
Let C.P of 1st watch=x
C.P of 2nd watch=840-x
S.P of 1st watch:
x×(100+16)/100=S.P1
116x/100=S.P1
S.P of 2nd watch:
(840-x)×(100-12)/100=S.P2
(840-x)×88/100=S.P2
Now According to question: There is no profit or loss
SO,
S.P1+S.P2=840
116x/100+(840-x)×88/100=840
116x+840×88-88x=840×100
28x=84000-73920
28x=10080
∴ x=360 Ans.
C.P of 2nd watch=840-x
=Rs(840-360)
=Rs 480 Ans.
2nd Method:
C.P of 1st watch at a profit 0f 16%=(3/7)×840
=Rs 360 Ans.
C.P of 2nd watch at a Loss of 12%=(4/7)×840
=Rs 480 Ans
OR
C.P of 2nd watch at a Loss of 12%=Rs(840-360)
=Rs 480 Ans.
(Q2) A man bought a horse and carriage for Rs 40000. He sold the horse at a gain of 10% and the carriage at a loss of 5%. He gained 1% on his whole transaction. The cost price of the horse was.
Solution: BY CONCEPT
Let C.P of horse=x
C.P of a carriage=40000-x
S.P of a horse:
x×(100+10)/100=S.P
11x/10=S.P
S.P of a carriage:
(40000-x)×95/100=S.P
Now According to question: he gained 1% on his whole transaction
So,
S.P of a horse+S.P of a carriage=40000×101/100
11x/10+(40000-x)×95/100=40000×101/100
11ox+40000×95-95x=40000×101
15x=40000×101-40000×95
=40000(101-95)
15x=240000
∴ x=Rs 16000 Ans
2nd Method:
C.P of a horse at a profit 0f 10%=(2/5)×40000
=Rs 16000 Ans.
Profit and Loss question with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.In this type, I have already shared a Profit and Loss question with a solution, Shortcut Tricks, Basic concept and frequently asked question if you have not read that yet, you should read it the right way here is the link.
Profit and Loss Problem Shortcut Tricks Type-3
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